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Donnie Reese
17,211 PointsTested answer, but can't get final challenge to pass. Am I doing something wrong?
I am trying to keep the return as concise as possible. I've tested the code in the console in workspaces and return the even indexes to the best of my knowledge. I thought it accounts for the length of the array like stated in another question, but it just tells me it didn't return the correct numbers.
I followed these steps in the code:
- check if number is even or odd by checking for remainder of length
- returned backwards count if it's even starting at the even ending
- else I reversed it and then counted forward by even indexes
- I tried to adjust the odd count incase i was hitting odds instead of even with no change to trial response.
- I searched forums
- I grimaced.
Any help would be appreciated.
def first_4(it):
return it[:4]
def first_and_last_4(it):
return it[:4] + it[-4:]
def odds(it):
return it[1::2]
def reverse_evens(it):
return it[-1::-2] if len(it) % 2 == 0 else it[::-1][::2]
2 Answers
Chris Freeman
Treehouse Moderator 68,428 PointsIt's not doing what you think:
>>> print(reverse_evens([1,2,3,4,5]))
[5, 3, 1]
>>> print(reverse_evens([1,2,3,4,5,6]))
[6, 4, 2]
Hint: think get even indexs first, then reverse it.
Nice use of slice of a slice!
Donnie Reese
17,211 PointsOh dang! I was thinking the problem was with the else condition and not with the even slice. Thanks Chris Freeman for helping out with the results. I was not iterating over the even indexes of the even slice, but the indexes of the even numbers. lol. Once I fixed it it was fine.