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iOS Swift Collections and Control Flow Introduction to Collections Working With Arrays

Posted by Tatenda Madzokere
Tatenda Madzokere
2,970 Points

Stuck again , i dont know what im doing wrong

var arrayOfInts: [Int] = [1, 2, 3, 4, 5, 6]

im new to swift is there something else i can do to better understand this

array.swift 
// Enter your code below
var arrayOfInts: [Int] = "1,2,3,4,5,6"

1 Answer

doesitmatter
doesitmatter
12,885 Points
doesitmatter
doesitmatter
12,885 Points

Ok so this challenge has 4 parts, in each part you are asked to do:

1. make a list. In swift to create a list you always start with brackets [] you put all the values you want in this list, seperated by a comma, like so:

 let myList = [1, 2, 3, 4]

2. add an item to the array you created in step (1) in two different ways. In swift to add an item to an array two ways are: using .append, or the + operator which is the most intuitive.

myList.append(5)
//myList  now contains:  [1, 2, 3, 4, 5]

myList += [6]
//myList  now contains:  [1, 2, 3, 4, 5, 6]
//NOTE: that  a += b is short for: a = a + b

3. retrieve a value from the array you created in step (1) and store it in a constant named value. To retrieve a value from a list or array in swift, all you need to do is write the name of the list and brackets [] with the index of the value you want to retrieve. NOTE that the index of the first item is 0 the second is 1 and the third is 2 etc.

let value = myList[0]
//value now contains 1
let value2 = myList[4]
//value2 now contains 5

4. remove a value from the array you created in step (1) and store it in a constant named discardedValue. Finally, to remove an element from swift, we use a function called remove(at: ). We call it on a list using a dot and pass it the index of the item we want to remove, the function then returns the value we removed from the list.

let discardedValue = myList.remove(at: 0)
//The list now contains: [2, 3, 4, 5, 6]
//discardedValue now contains 1

let discardedValue2 = myList.remove(at: 3)
//The list now contains: [2, 3, 4, 6]
//discardedValue2 now contains 5