'random.randit()' problem

Question

Hey! I think i didn't understand 100% this question. the 'len' of apple minus one is 3, so i set number 0,3. what exaxly i need to return?

thanx!

item.py

import random

def random_item("apple"):
    random.randit(0,3)
    return "apple"



# EXAMPLE
# random_item("Treehouse")
# The randomly selected number is 4.
# The return value would be "h"

Answer 1 · 2016-12-29T20:27:58Z

December 29, 2016 8:27pm

Hi or porat,

The example text in the code challenge is just there to show you what the expected output should be if the function argument happened to be "Treehouse". They don't actually want you to input a string, nor do they want you to preset the limits of the random integer.

1) Your function should take one argument, you can name it whatever you want. The important thing is that you don't know what it will actually be when the function is tested in the code checker. All you know is that it is iterable, like a string or a list.

2) Figure out the length of the iterable argument.

3) Get a random number between 0 and the length of the argument minus 1. Note that you have a typo in random.randint(). You forgot the "n".

4) Whatever that random number turns out to be, that will be used as an index value. You then need to return whatever member (letter or list item) happens to be at that index in the iterable.

Hope this helps get you started.

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'random.randit()' problem

1 Answer

Ryan S

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