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Python Introducing Lists Build an Application Multidimensional Musical Groups

Grayden Kellogg
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Grayden Kellogg
Python Development Techdegree Student 1,826 Points
Posted by Grayden Kellogg
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Grayden Kellogg
Python Development Techdegree Student 1,826 Points

Joining items in a multi-dimensional list.

Not sure where to go from here.

groups.py 
musical_groups = [
    ["Ad Rock", "MCA", "Mike D."],
    ["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
    ["Salt", "Peppa", "Spinderella"],
    ["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
    ["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
    ["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
    ["Run", "DMC", "Jam Master Jay"],
]
# Your code here
group_members = ", ".join(musical_groups)

for groups in musical_groups:
    print(group_members)
Grayden Kellogg
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.a{fill-rule:evenodd;}techdegree
Grayden Kellogg
Python Development Techdegree Student 1,826 Points
Grayden Kellogg
.a{fill-rule:evenodd;}techdegree
Grayden Kellogg
Python Development Techdegree Student 1,826 Points

I'm supposed to loop through each group and output the members joined together with a ", " comma space as a separator. Pretty lost

2 Answers

Steven Parker
Steven Parker
230,688 Points
Steven Parker
Steven Parker
230,688 Points

Here's a few hints:

  • notice that "musical_groups" is a big list of smaller lists
  • if you looped through the big list, your loop variable would hold a smaller list
  • you could then join and print each smaller list
Grayden Kellogg
seal-mask
.a{fill-rule:evenodd;}techdegree
Grayden Kellogg
Python Development Techdegree Student 1,826 Points
Grayden Kellogg
.a{fill-rule:evenodd;}techdegree
Grayden Kellogg
Python Development Techdegree Student 1,826 Points

As I was typing a reply I figured it out. Thank you for your help. I thought the way the multidimensional list was made was a little confusing. But it worked out. Thanks!

Alex Curtis
Alex Curtis
524 Points
Alex Curtis
Alex Curtis
524 Points

I still can't get this to work correctly, my approach is if the index is an odd number then join it with the other values of an odd index but that works in code but it fails the question, I was also trying to pass the index number to a function I defined which worked but didn't pass the challenge? Is there only 1 right answer for this?

Steven Parker
Steven Parker
230,688 Points
Steven Parker
Steven Parker
230,688 Points

Sounds like you're getting to fancy. The challenge just wants you to show each list of members for task 1, and for task 2 do the same but only for groups with 3 members. There's no "even" or "odd" testing needed.

If you're still having trouble, start a fresh question (you should never add a question as an "answer") and be sure to show your code.