It says compile error.
if (firstExample.equals("secondExample")) {console.printf("first is equals to second");

Question

This is the "Challenge Task" 1 of 2 question.
After I wrote the following, it says compile error.
Could you kindly advise which part I have done wrong?
String firstExample = "hello";
if (firstExample.equals("secondExample")) {console.printf("first is equals to second");
                                          System.exit(0);}
String secondExample = "hello";
```Equality.java
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
if (firstExample.equals("secondExample")) {console.printf("first is equals to second");
                                          System.exit(0);}
String secondExample = "hello";
String thirdExample = "HELLO";
```

Yanuar Prakoso · Answer

Hi Zixi
First of all in your IF statement you should not use double quotes ("secondExample") because you want to compare with the value inside variable called secondExample which = "hello". Then you must put your IF statement below the String secondExample since you want to compare it with firstExample. Therefore the compiler needs to know what is secondExample is. Better yet for best practice you write your IF statement after String thirdExample.
And then in the task you only required to print ("first is equals to second"). You do not need to add System.exit(0)
I retry your challenge and here is what I came up with:
```java
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
if (firstExample.equals(secondExample)) {
  console.printf("first is equals to second");
}
```
I hope this can help

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Zee Liu

Zee Liu

It says compile error. if (firstExample.equals("secondExample")) {console.printf("first is equals to second");

1 Answer

Yanuar Prakoso

Yanuar Prakoso

Zee Liu

Zee Liu