I cant find whats wrong with my code:

The following will pass the challenge:

def first_4(list):
    return list[0:4]

def first_and_last_4(list):
    first = first_4(list)
    second = list[-4:]
    return first + second

def odds(list):
    return list[1::2]

def reverse_evens(list):
    return list[-1::-2]

The following would be test case safe:

def reverse_evens(list):
    try:
        if len(list) % 2 != 0:
            reverse_even = list[-1::-2]
        else:
            reverse_even = num[-2::-2]
    except ValueError:
        print("Non iterable item")
    else:
        return reverse_even

Or even another way to solve this is to get the even indices with a slice [::2] and then return a slice in reverse order [::-1]

def reverse_evens(list):
    list = list[::2]
    return list[::-1]

I hope this helps.

Hello

the code above assumes all you are always passing numeric values and it is returning the even values (not the indexes). I mis-read the question.

you case is much simpler ... this is all you need

def reverse_evens(item):
    return(item[-1::-2])


this the the full 4 questions
def first_4(item):
    return item[:4]
def first_and_last_4(item):
    return(item[:4] + item[-4::])
def odds (item):
    return(item[1::2])
def reverse_evens(item):
    return(item[-1::-2])

def reverse_evens(list4): if(len(list4)%2==0): return list4[len(list4)-2::-2] else: return list4[len(list4)-1::-2] // this is the answer :)

Hello

You almost there

try this ....

def reverse_evens(list4):
    new_list= []
    for item in list4[::-1]:
        if item % 2 !=0 :
            new_list.append(item)
    return new_list

print(reverse_evens([1, 2, 3, 4, 5]))   #<<<<<<<<< for demo only

if you are not familiar with the % operator, it returns the reminder from a div operation. You can google it.

if this answers your question, please mrk question as answered.