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Erik Luo
3,810 Pointshow to create a function named random_item that takes a an iterable as argument?
how to create a function named random_item that takes a an iterable as argument?
# EXAMPLE
# random_item("Treehouse")
# The randomly selected number is 4.
# The return value would be "h"
import random
def random_item(arg):
random.randint(0, len(arg))
return arg
2 Answers
Chris Freeman
Treehouse Moderator 68,457 PointsYou have the basic form of the answer. The task asks Then use random.randint() to get a random number between 0 and the length of the iterable, minus one. Return the iterable member that's at your random number's index.
You need to
- subtract 1 from the
len(arg) - assign the random result to a variable so it can be used to reference into the iterable argument. You can use "
idx" as a common abbreviation for "index":idx = random.randint.... - return the indexed item from iterable:
return arg[idx]
Thomas Fildes
22,687 PointsHi Erik,
This challenge is a tricky one to pass but remember it asks you to return an integer between 0 and the iterable MINUS 1. Here is the code below:
import random
def random_item(arg):
return arg[random.randint(0, len(arg)-1)]
As you can see this can be achieved all on one line of code inside the function.
Hope this helps. Happy Coding!
Erik Luo
3,810 PointsThank you
Erik Luo
3,810 PointsErik Luo
3,810 PointsThank you