How do I return list value and index to use as conditions?

Question

I'm trying to avoid printing the first iten of a list if its idex is 0 and if it's the letter 'a'.

However, I don't know why my code bellow doesn't work.

def loopy(items):
    for iten in items:
        if items.index(iten) == 0 and iten == 'a':
            continue
        else:
            print(iten)

Anyone could help me?

breaks.py

def loopy(items):
    # Code goes here

Answer 1 · 2016-09-08T15:58:36Z

September 8, 2016 3:58pm

Hey Marcelo,

(I added markdown to your post, so the code is more readable. You can see how in the Markdown Cheatsheet.)

There are a few things going on here. First, there is a spelling error in your code. You have iten instead of item and this matters in code challenges.

Second, you aren't checking for a index, the challenge wants you to check the value at a specific index. In this case, it wants you to see if the value at index 0 is an "a" or not. So it's just a single if statement to check one thing.

Other than that, you are on the right track.

Below is the corrected code for your reference. I hope it all makes sense.

def loopy(items):
    # Code goes here
    for item in items:
        if item[0] == "a":
            continue
        else: 
            print(item)

Keep Coding! :)

Answer 2 · 2016-09-08T17:01:15Z

September 8, 2016 5:01pm

While you are at it, check out enumerate if you are evaluating items and their indexes

Answer 3 · 2016-09-08T22:18:00Z

September 8, 2016 10:18pm

Fellows,

Thanks for the help.

I hope one day be abble to help other people like you guys.

Regards

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Marcelo Alves

Marcelo Alves

How do I return list value and index to use as conditions?

3 Answers

Jason Anders

Jason Anders

John Simmons

John Simmons

Marcelo Alves

Marcelo Alves