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JavaScript

Posted by Johnny Baltazar
Johnny Baltazar
2,504 Points

Finding the sum of a "counter" variable loop that ran ten times then was pushed into the "numbers" array.

Hi everyone, I'm asking for help to find the sum of an array with elements that were pushed from a counter variable that had previously looped 10 times. I'm new to Javascript and was practicing for an assessment, and I've tried several different ways to do it and have only resulted with just a list of the elements within the numbers array. The following code is where I'm at. Thanks in advance.

var counter = 10;
var numbers = [];

for (i = 1; i <= 10; i ++) {
  counter = [i + 73];
  numbers.push(counter);
}

console.log(numbers);

function sum(arr) {
  var s = 0;
  for(var i = 0; i < arr.length; i++) {
     s = s += arr[i];
  }
  return s;
}

console.log(sum([numbers]));

function getArraySum(a) {
  var total = 0;
  for (var i in a) {
    total += a[i];
  }
  return total;
}

var numbers = getArraySum([numbers]);
console.log(numbers);

1 Answer

jb30
jb30
44,806 Points
jb30
jb30
44,806 Points

In your first for loop, you have 

counter = [i + 73];
numbers.push(counter);

which sets an array to counter and adds it to your numbers array. If you wanted to add a number directly to the numbers array, you could try counter = i + 73;

Instead of console.log(sum([numbers])); and var numbers = getArraySum([numbers]);, have you tried console.log(sum(numbers)); and var numbers = getArraySum(numbers);? If you use [numbers], then it would create an array whose first element is the array numbers.

In your getArraySum function, you have

  for (var i in a) {
    total += a[i];
  }

Try using total += i; instead, since i is already an element of a.

In your sum function, you have s = s += arr[i]; This doesn't cause any problems, but the s = at the beginning is redundant. You probably meant either s = s + arr[i]; or s += arr[i];

Johnny Baltazar
Johnny Baltazar
2,504 Points

Thanks for the help JB30!