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Vardas Pavarde
641 PointsCreate a for loop that logs the numbers 4 to 156 to the console. To log a value to the console use the console.log( )
Create a for loop that logs the numbers 4 to 156 to the console. To log a value to the console use the console.log( ) method.
8 Answers
sizwengubane
15,244 PointsIn this case, you have to create a counter variable called 'i' inside the loop and set its starting value to 4, then u have to create a condition saying 'i <= 156', next you need to increment the value stored inside i by one each time the loop runs.
for( var i = 4; i <= 156; i++){
console.log(i);
}
Mark my answer as the best if i managed to help u
Solomon Ray
4,021 PointsHey Guys!
this is how i did it:
for ( var i = 4 ; i <= 156; i += 1 ) { console.log( i ); }
Amar Mohammed
6,795 PointsThat worked, thank you!!!
karson Adam
32,623 Pointsyou need to create for loop and start with initial value i = 4 and stop when i is 156 ,and print i each time
for ( i = 4 ; i< 157; i++){
console.log(i);
}
KARMA DRUKPA
7,235 Pointsfor (let i = 4; i <157; i++){
console.log(i);
}
I Don't know why this code is not working, it should definitely work as of my best knowledge. TreeHouse is not marking as right answer.
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Kamal Ghimire
12,143 Pointsfor ( let i = 5 ; i <= 100; i++ ) { console.log( i ); }
This can solve your problem. It shows that there should be an increment of (i) up to 100 times. I tried on the console of chrome developer tools.
Nasheed Rashad
11,243 Pointsthis is the only one that worked for me - thank you!
kathyvuong
9,299 PointsTry this, for ( var i = 4; i <= 156; i += 1; ) { console.log(i); }
kathyvuong
9,299 PointsThis is a correct answer. You can try it.
for ( var i = 4; i <= 156; i += 1; ) { console.log(i); }
Richard Wong
Full Stack JavaScript Techdegree Student 1,888 PointsAhhhh I left out the 'var' part in the first part of the for loop