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Python Python Collections (2016, retired 2019) Lists Disemvowel

Posted by prateekmahesh
prateekmahesh
5,454 Points

Can I have the solution?

Can someone help me with this task?

disemvowel.py 
def disemvowel(word):
    for i in word:
        if i == "a" or i == "A" or i == "e" or i == "E" or i == "i" or i == "I" or i == "o" or i == "O" or i == "u" or i == "U":
            word.remove(i)
    return word

2 Answers

Alexander Davison
Alexander Davison
65,469 Points

You can't call remove on a string, but you can do it on lists.

Try making a new variable called result (you can call it whatever you want; I like it to be called result) and use it to store the value of word in a list form. To convert strings to lists, you can use the list function (as shown in Figure 1). Then, replace all usages of word after this line of code with result (or whatever you called it).

Figure 1:

>>> list('abc')
['a', 'b', 'c']
>>> list('prateek is cool')
['p', 'r', 'a', 't', 'e', 'e', 'k', ' ', 'i', 's', ' ', 'c', 'o', 'o', 'l']

I hope this helps.

If you need further help, please reply. I'd be happy to help furthermore. :smile:

~Alex

Samuel Focht
Samuel Focht
4,321 Points
Samuel Focht
Samuel Focht
4,321 Points 
def disemvowel(word):
    new_word = "" 
    for letter in word: 
        if letter not in 'aeiouAEIOU':
            new_word += letter 
    return new_word

Ok what I did was iterate over our variable word. Now important!!!!!! You can't change a string. So I made a new variable. I tested each letter to see if it was a vowel if it wasn't (not in) it was added to new_word. Hope this helped.