Bummer! Hmm, got back letters I wasn't expecting!

As the array has only lowercase letters, it might be a good idea to move the .lower() to the letter inside the if-statement. Because we have to see if the lowercase version of the letter is present in the array (that has just lowercase versions).

Maybe this works?

def disemvowel(word):
    vowels = ['a', 'e', 'i', 'o', 'u']
    keep_list = []
    for letter in word:
        if letter.lower() not in vowels:
            keep_list.append(letter)

    return ''.join(keep_list)

print(disemvowel("I can haz Cheeseburger")) # prints cn hz Chsbrgr

The original code turns the entire word to .lowercase before looping over it. However, this will result in the return-value being all-lowercased. This is not desirable because the assignment only requires the vowels to be removed. The capitalization should still be identical.

Right before the moment that you check if a letter is a vowel, you should lowercase it. Which is inside the if-block.

I can imagine this is a little bit confusing, but you could try to put print()-statements inside your function and print the values. This can often clarify what is happening.

It doesn't work the first way because in your program you are only returning lowercase letters. I'll show an example.

my_func is the function that will pass the challenge, and your_func is the function that WON'T pass the challenge.

Assume I'm in the Python shell

>>> my_func("hello world")
"hll wrld"
>>> your_func("hello world")
"hll wrld"
>>> my_func("HELLO world")
"HLL world"
>>> your_func("HELLO world")
"hll wrld"
>>> my_func("HeLlO WoRlD")
"HLl WRlD"
>>> my_func("Impossible")
"mpssbl"

I hope this clears things up

Happy C0D1NG!

~Alex

Hello there,

Just an observation as I'm not really familiar with python:

It seems you are missing something between the parentheses in the .append()-method. Did you mean to .append(letter)?

Greets, Rogier