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785 PointsYou must return the dimensions using the $size parameter
I really don't understand this error. I compiled my code on a server and it works.
<?php
class Render {
public static function displayDimensions($size){
$result = $size['length'].' x '. $size['width'];
return $result;
}
}
$size = array (
'length' => 12,
'width' => 14
);
echo Render::displayDimensions($size);
?>
2 Answers
Jaro Schwab
8,957 PointsHeja..
For the challange, you dont need to specify the $size array yourself.. Just give it as a param, and then you need to access the first (length) and the second (width) item in this array.. so, this code should probably do the trick:
<?php
class Render {
public static function displayDimensions($size){
$result = $size[0].' x '. $size[1];
return $result;
}
}
echo Render::displayDimensions($size);
Tori Tech S.A.C.
4,316 Pointsmeh... why did the problem says "The accepted parameter $size will be an array containing length and width in that order!" thats confusing! I was doing the same thing and I couldn't see what was wrong....