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michaelangelo owildeberry
18,173 Pointswrite a function named numbers() that takes two arguments: a count as an integer and a string. Return a match for exactl
write a function named numbers() that takes two arguments: a count as an integer and a string. Return a match for exactly count numbers in the string. Remember, you can multiply strings and integers to create your pattern.
Not returning number, please help =)
import re
def first_number(s):
return re.search(r'\d', s)
def numbers(count=5, string):
return re.search(r"\w" * 5, string)
5 Answers
William Li
Courses Plus Student 26,868 PointsYou had it mostly right, but I think you got carried away by what the example is saying
For example: r"\w" * 5 would create r"\w\w\w\w\w".
what this challenge is asking for actually isn't all that different than the previous one
def numbers(count, string):
return re.search(r"\d" * count, string)
michaelangelo owildeberry
18,173 Pointsthat was frustrating at first since I thought you did the exact thing as me, just in different format... now I see the escape character
Adam Oliver
8,214 PointsI don't understand why I'm not getting the correct answer back. It says 'auo' returned?
import re
def first_number(my_str):
return re.search(r'\d', my_str)
def numbers(count, my_str):
return re.match(r'\w' * count, my_str)
Adam Oliver
8,214 PointsThanks. I also was fooled by the 'match' in the objective and added that to my code instead of search.
Kenneth Love
Treehouse Guest TeacherIt's hard to talk about because what's returned is literally a Match object, whether it comes from re.match() or re.search().
michaelangelo owildeberry
18,173 Pointson the second return you are using ...r'\w'... which says you are looking for unicode characters... you want a different escape character instead of w