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Python Dates and Times in Python (2014) Dates and Times Timedelta Minute

Write a function named minutes that takes two datetimes and, using timedelta.total_seconds() to get the number of second

Can't seem to get this right for 2days now

minutes.py
import datetime

def minutes(dt1, dt2):
    seconds = datetime.timedelta.total_seconds(dt1 - dt2)
    return round(minutes * 60)

1 Answer

Jennifer Nordell
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STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there, Kennedy Malonga! I can tell you've worked on this. In fact, I think you may have overthought this a little bit.

The first line inside the minutes method is almost perfect. But as the instructions say, you should subtract dt1 from dt2. So instead of (dt1 - dt2) you will need (dt2 - dt1). That will give you the correct number of seconds.

In your final statement, you're using return to send back minutes times 60 and rounded. The name minute is defined but it's the name of the method you're currently in. What I think you meant was that you wanted to round the seconds. The math here is also not quite right. To get the number of minutes you need to divide the number of seconds by 60 not multiply minutes by 60. For instance, if I told you that I had been waiting for 210 seconds. That would mean I'd been waiting 3 minutes and 30 seconds. 210 divided by 60 is equal to 3.5.

Instead of round(minutes * 60) I'm expecting to see round(seconds / 60).

Hope this helps! :sparkles: