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Java Java Basics Getting Started with Java Strings and Variables

Learning coding
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Learning coding
Front End Web Development Techdegree Student 9,937 Points
Posted by Learning coding
.a{fill-rule:evenodd;}techdegree
Learning coding
Front End Web Development Techdegree Student 9,937 Points

Why isn't this code working?

Hi,

I would like to use the escape sequence \n in order to have the firstName and the lastName on different lines in the output. That looks cleaner, but I get errors from the console when I try to use the escape sequence.

import java.io.Console;

public class Introductions {

public static void main(String[] args) {
    Console console = System.console();

String firstName = console.readLine("Enter your first name: "); String lastName = console.readLine("Enter your last name: "); console.printf("First name: %s", firstName\n"); console.printf("Last name: %s", lastName\n"); } }

3 Answers

Eva Kadar
Eva Kadar
8,272 Points
Eva Kadar
Eva Kadar
8,272 Points

Hi Rene,

the \n should be between the %s and the apostrophe and you don't need the apostrophe after it either.

Try something like this:

import java.io.Console;

public class Introductions {

public static void main(String[] args) {
    Console console = System.console();

String firstName = console.readLine ("Enter your first name: "); 
String lastName = console.readLine ("Enter your last name: "); 
console.printf("First name: %s %n", firstName); 
console.printf("Last name: %s %n", lastName); 
} 
}
Eva Kadar
Eva Kadar
8,272 Points
Eva Kadar
Eva Kadar
8,272 Points

You can use both, it means the same, I just prefer the %n - and yes, Craig starts to use it as well. Anyway, its up to you I think. :)