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Start your free trialNick Woody
2,302 PointsWhy doesn't this work?
Having trouble with this code challenge:
EXAMPLES
squared(5) would return 25
squared("2") would return 4
squared("tim") would return "timtimtim"
def squared(arg): try: int(arg) return arg * arg except ValueError: return arg * len(arg)
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(arg):
try:
int(arg)
return arg * arg
except ValueError:
return arg * len(arg)
1 Answer
Alexander Davison
65,469 PointsYou are doing great!
But be careful: When you call int(arg)
, it doesn't modify arg
's value, it returns a new value.
This means you should remove int(arg)
, and replace this:
return arg * arg
as this.
return int(arg) * int(arg)
Or you could simply use the exponent operator for less typing:
return int(arg) ** 2
I hope this helps!
Happy coding! ~Alex
Nick Woody
2,302 PointsNick Woody
2,302 PointsThanks! :D
Alexander Davison
65,469 PointsAlexander Davison
65,469 PointsNo problem