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PHP Integrating PHP with Databases Limiting Records in SQL Pagination Function

Alfredo Prince
Alfredo Prince
6,175 Points

Why does it say "Task 1 is no longer passing"?

I returned the function and passed all of the values.....Why is this not working?

index.php
<?php
include "pagination.php";

/* add function here */
function pagination ($total_pages, $current_page, $section, $search){
  $pagination = "<div class=\"pagination\">";
$pagination .= "Pages: ";  
for ($i = 1;$i <= $total_pages;$i++) {
    if ($i == $current_page) {
        $pagination .= " <span>$i</span>";
    } else {
        $pagination .= " <a href='catalog.php?";
        if (!empty($search)) {
            $pagination .= "s=".urlencode(htmlspecialchars($search)) . '&' ;
        } else if (!empty($section)) {
            $pagination .= "cat=".$section . '&';
        }
        $pagination .= "pg=$i'>$i</a>";
    }
}
$pagination .= "</div>";
}

/* setting pagination variable */


$pagination = pagination();

/* displaying the pagination */
return pagination ($total_pages, $current_page, $section, $search);

1 Answer

Cindy Lea
PLUS
Cindy Lea
Courses Plus Student 6,497 Points

That usually means you have a syntax/typo error somewhere.

Heres the code to pass task 1 & 2:

<?php include "pagination.php";

/* add function here / function pagination($total_pages, $current_page, $section, $search){ / setting pagination variable */ $pagination = "<div class=\"pagination\">"; $pagination .= "Pages: ";
for ($i = 1;$i <= $total_pages;$i++) { if ($i == $current_page) { $pagination .= " <span>$i</span>"; } else { $pagination .= " <a href='catalog.php?"; if (!empty($search)) { $pagination .= "s=".urlencode(htmlspecialchars($search)) . '&' ; } else if (!empty($section)) { $pagination .= "cat=".$section . '&'; } $pagination .= "pg=$i'>$i</a>"; } } $pagination .= "</div>";

return $pagination; }

/* displaying the pagination */ echo pagination($total_pages, $current_page, $section, $search);