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JavaScript JavaScript Array Iteration Methods Combining Array Methods Combining filter() and reduce()

Elliott Tuan
Elliott Tuan
7,790 Points
Posted by Elliott Tuan
Elliott Tuan
7,790 Points

Why can't I return the highest price with teacher's method in video?

If I want to return the highest price product, it works.

--

const products = [ { name: 'hard drive', price: 59.99 }, { name: 'lighbulbs', price: 2.59 }, { name: 'paper towels', price: 6.99 }, { name: 'flatscreen monitor', price: 159.99 }, { name: 'cable ties', price: 19.99 }, { name: 'ballpoint pens', price: 4.49 } ];

const highestPrice = products .reduce((highest, product) => { if (highest.price > product.price){ return highest } return product })

console.log(highestPrice) //return { name: 'flatscreen monitor', price: 159.99 }

--

But, if I want to return just a number of price instead an object, it's not work!

--

const products = [ { name: 'hard drive', price: 59.99 }, { name: 'lighbulbs', price: 2.59 }, { name: 'paper towels', price: 6.99 }, { name: 'flatscreen monitor', price: 159.99 }, { name: 'cable ties', price: 19.99 }, { name: 'ballpoint pens', price: 4.49 } ];

const highestPrice = products .reduce((highest, product) => { if (highest.price > product.price){ return highest.price } return product.price })

console.log(highestPrice) //return 4.49

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

Think about what highest represents. In the first example, it is always one of the products objects. But in the second example, after the first iteration it becomes a price value instead. So from then on, the comparison highest.price > product.price doesn't make sense. The function needs to be modified to make the first argument a price instead of an object. And, this is also a great place to use a ternary expression:

const highestPrice = products.reduce( (highPrice, product) =>
                           (highPrice > product.price) ? highPrice : product.price,
                         0);        // start with 0 for highPrice
Elliott Tuan
Elliott Tuan
7,790 Points
Elliott Tuan
Elliott Tuan
7,790 Points

Thank you Parker! I haven't learn about ternary expression, and although I still can't clearly explain the mistake of my thinking in the question upon, I still try to think what you've said "modify the argument to be a price instead of an object", and here's my solution:

I use .map() to make it price value only.

const products = [ { name: 'hard drive', price: 59.99 }, { name: 'lighbulbs', price: 2.59 }, { name: 'paper towels', price: 6.99 }, { name: 'flatscreen monitor', price: 159.99 }, { name: 'cable ties', price: 19.99 }, { name: 'ballpoint pens', price: 4.49 } ];

const highestPrice = products .map(obj => obj.price ) .reduce((highest, price) => { if (highest > price){ return highest } return price })

console.log(highestPrice)

-- Return is right, is my thinking right too?

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

Sure, that works too. Just for comparison, here's the reduce-only version without the ternary:

const highestPrice = products.reduce((highest, price) => {
  if (highest > product.price) return highest; return product.price;
}, 0);

And when posting code, always use Markdown formatting to preserve the code's appearance and retain special symbols (as I have done here).

Here's the MDN page for the conditional operator to create ternary expressions.