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![Jacob Clinton](https://secure.gravatar.com/avatar/f19a2fab9973258e39ebf0b3b473e163?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Jacob Clinton
4,531 PointsWhy aren't the other lists being joined?
(It was working but apparently I'm not allowed to use a nested for loop I have to use join). When I run my program only the members of the last group are being printed ("Run, "DMC" ect) but what happened to everyone else?
musical_groups = [
["Ad Rock", "MCA", "Mike D."],
["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
["Salt", "Peppa", "Spinderella"],
["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
["Run", "DMC", "Jam Master Jay"],
]
# Your code here
seperator = ", "
for group in musical_groups:
all_people = seperator.join(group)
print(group)
1 Answer
![Chris Freeman](https://uploads.teamtreehouse.com/production/profile-photos/1153532/micro_image.jpg)
Chris Freeman
Treehouse Moderator 68,425 PointsHi Jacob Clinton, I see two issues:
- The value of
all_people
is overwritten each time the loop is run. - the final
print
referencesgroup
, which contains the value ofgroup
on the last iteration of the loop.
Perhaps, you meant in indent the print
statement so it runs in every loop iteration, and it should print all_people
instead of group
.
Post back if you need more help. Good luck!!