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![Michel Spaniolo](https://secure.gravatar.com/avatar/9327d069dbbd5a6e3e217e5dbb25846f?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Michel Spaniolo
Courses Plus Student 1,850 PointsWhen i compile this code i get errors. I dont see whats wrong though..Can someone look at my link..https://w.trhou.se/qn
https://w.trhou.se/qnfilxe28k i compile my code and i get the following errors...I Checked my code for errors and i didnt catch anything ...all the semicolons are there.
Picked up _JAVA_OPTIONS: -Xmx128m
Introductions.java:8: error: unclosed string literal
String firstName = console.readLine("What is your name? );
^
Introductions.java:8: error: ';' expected
String firstName = console.readLine("What is your name? );
^
Introductions.java:9: error: illegal start of expression
console.printf("Hello, my name is %s\n");
^
Introductions.java:9: error: ';' expected
console.printf("Hello, my name is %s\n");
^
4 errors
1 Answer
![Steven Parker](https://uploads.teamtreehouse.com/production/profile-photos/969492/micro_tool_chess_set_2.jpg)
Steven Parker
230,688 PointsThe compiler is showing you the problem. When it says "unclosed string literal" , it means something is missing:
String firstName = console.readLine("What is your name? );
// ^^
// missing ending quote mark!
It points to the beginning of the string since it doesn't know how to tell where the ending should be.