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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Gasly gelin
Gasly gelin
7,923 Points

What's wrong with this this program? The program returns the correct values. but treehouse says otherwise

Bummer: Hmm, didn't get the expected output. Be sure you're lowercasing the string and splitting on all whitespace!

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(passing_string):
    passing_string = passing_string.lower()
    passing_string = passing_string.split(' ')
    dictionary = {}

    for word in passing_string:
        num = passing_string.count(word)
        dictionary.update({word:num})
    return dictionary

1 Answer

Oskar Lundberg
Oskar Lundberg
9,534 Points
Oskar Lundberg
Oskar Lundberg
9,534 Points

Hello Gasly! The problem is that you are splitting the string on all blankspaces, not whitespaces. Your function surely returns the right value when the example string is being used, but might not for some other string. If you just do one small change, your code will pass perfectly.

    passing_string = passing_string.split()

^ This splits on all whitespaces, like blankspaces, tabs and newlines (Use this above method)

    passing_string = passing_string.split(' ')

^This only splits on blankspaces. Hope this helps :D

Gasly gelin
Gasly gelin
7,923 Points

Thanks for the help!