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Start your free trialKonrad Pilch
2,435 PointsWhats wrong with this code?
Whats wrong with this code? Why isn't it echo out the recipes level?
<li><i class="fa fa-bolt"></i><strong>Level:</strong><?php echo get_field('recipes_level'); ?></li>
2 Answers
Tiffany McAllister
25,806 PointsHave you tried 'the_field' instead of 'get_field'?
Zac Gordon
Treehouse Guest TeacherIf it is returning an array then you need to loop through it. You may have a field that accepts multiple images?
Konrad Pilch
2,435 PointsI think it does go throw the loop? or is there a special on for it? i mean, in the recent project this doenst work.
<?php if ( have_posts() ) : while ( $the_query->have_posts() ) : $the_query->the_post(); ?>
<div class="col-xs-6 col-md-3 new-portfolio">
<div class="project-tab">
<a href="<?php the_permalink(); ?>"><h4><?php the_title(); ?></h4></a>
<a href="<?php the_permalink(); ?>">
<img class="portolio-image" src="assets/img/webpor.jpg">
</a>
<a href="<?php the_permalink(); ?>">
<?php $value = get_field( "image" ); ?>
<?php echo $value ?>
<img class="portolio-image-secondary" src="assets/img/webpor.jpg">
</a>
</div><!-- /project-tab -->
</div><!-- /col-xs-6 col-md-3 -->
<?php endwhile; endif;?>
Konrad Pilch
2,435 PointsKonrad Pilch
2,435 PointsIts displaying array all the time, but i know it should work , because i pulled an image
<a href="<?php the_permalink(); ?>"><img src="<?php echo get_field('recipes_image'); ?>"></a>
ANd thas working, but it wont work for my description which i svery unusual : p but im also quite a newbie as well