Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript JavaScript and the DOM (Retiring) Getting a Handle on the DOM Selecting Multiple Elements

Kornel L
Kornel L
4,368 Points

What is the solution to this challenge?

?

index.html
<!DOCTYPE html>
<html>
  <head>
    <title>Rainbow!</title>
  </head>
  <body>
    <ul id="rainbow">
      <li>This should be red</li>
      <li>This should be orange</li>
      <li>This should be yellow</li>
      <li>This should be green</li>
      <li>This should be blue</li>
      <li>This should be indigo</li>
      <li>This should be violet</li>
    </ul>
    <script src="js/app.js"></script>
  </body>
</html>
js/app.js
let listItems = document.querySelectorAll('rainbow');
const colors = ["#C2272D", "#F8931F", "#FFFF01", "#009245", "#0193D9", "#0C04ED", "#612F90"];

for(var i = 0; i < colors.length; i ++) {
  listItems[i].style.color = colors[i];    
}

2 Answers

Umesh Ravji
Umesh Ravji
42,386 Points

Hi Kornel, this challenge requires you to select all of the list item elements (li) inside the unordered list (ul).

let listItems = document.querySelectorAll('rainbow');

That code will actually return empty, as you need the # to select based on an elements ID. In order to get a list of all the li elements inside the unordered list, you can use the code below:

let listItems = document.querySelectorAll('#rainbow li');

Since this is only one list on the page, the following code works too:

let listItems = document.querySelectorAll('li');
Kornel L
Kornel L
4,368 Points

Thank You @Umesh Ravji! I don't remember this being mentioned during the course ('#rainbow li') adding 'li' at the and so you helped a lot.