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Java Java Basics Perfecting the Prototype String Equality

Posted by Sarah Strange
Sarah Strange
Courses Plus Student 352 Points

What is the problem

Seems to be correct to me don't know what the next step is

Equality.java 
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
if (firstExample == secondExample) {
  console.printf("First is equal to second");
}

if (firstExample.equalsIgnoreCase == thirdExample.equalsIgnoreCase) {
  console.printf("First and third are the same ignoring case");
}
Mike Papamichail
Mike Papamichail
4,883 Points
Mike Papamichail
Mike Papamichail
4,883 Points

The first condition inside the first if statement, seems to be correct.However, inside your second if statement you are calling the .equalsIgnoreCase() method on the String firstExample to check-from what i understand- if that firstExample String is equal to the thirdExample one. So, as i've already metnioned .equalsIgnoreCase() is a method and it takes in a String argument to test equality.In order for your code to work correctly you need to do the following :

if (firstExample.equalsIgnoreCase(thirdExample)) {
  console.printf("First and third are the same ignoring case");
}