Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Posted by Mikael Ritvos
Mikael Ritvos
95 Points

What do I write here?

I want to progress

Name.java 
// I have setup a java.io.Console object for you named console
String firstName = "Mikael";
printf "Mikael can code in Java!"
 console.printf("Mikael, can code in Java!");

1 Answer

Liam Clarke
Liam Clarke
19,938 Points
Liam Clarke
Liam Clarke
19,938 Points

First part. So you have done the first part correct defining a string variable your name.

String firstName = "Mikael";

Second part. This is where you went wrong! Remove your second line and you are pretty much there.

String firstName = "Mikael";
console.printf("<YOUR NAME> can code in Java!");

Third part. On this part you simply change the <YOUR NAME> with the variable you just created, using the string formatter which you learnt in previous videos.

String firstName = "Mikael";
console.printf("%s can code in Java!", firstName);

Does that look familiar? The %s is the formatter for a simple string. The variable is firstName you created above.