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Start your free trialZane DeVault
42,331 PointsUsing next() is causing a PHP Notice.
When I add the conditional:
if ( next($tasks)['project_id'] != $item['project_id'] ) {
I get a PHP Notice that reads:
Notice: Trying to access array offset on value of type bool
It seems like when calling the next() function in the conditional it doesn't just check the next array item, but actually moves the pointer to the next array item. When this happens the next($tasks) variable becomes a boolean and not an array and calling the 'project_id' key on the boolean is causing the notice.
Any advice on why this is happening will be greatly appreciated.
Here is the full code from my reports.php file for reference:
<?php
require 'inc/functions.php';
$page = "reports";
$pageTitle = "Reports | Time Tracker";
$filter = 'all';
if( !empty($_GET['filter']) ) {
$filter = explode(':', filter_input(INPUT_GET, 'filter', FILTER_SANITIZE_STRING));
}
include 'inc/header.php';
?>
<div class="col-container page-container">
<div class="col col-70-md col-60-lg col-center">
<div class="col-container">
<h1 class='actions-header'>Reports on <?php
if(!is_array($filter)) {
echo "All Tasks by Project";
} else {
echo ucwords($filter[0]) . " : ";
switch ($filter[0]) {
case 'project':
$project = get_project($filter[1]);
echo $project['title'];
break;
case 'category':
echo $filter[1];
break;
case 'date':
echo $filter[1] . " - " . $filter[2];
break;
}
}
?></h1>
<form class="form-container form-report" action="reports.php" method="get">
<label for="filter">Filter:</label>
<select id="filter" name="filter">
<option value="">Select One</option>
<optgroup label="Project">
<?php
foreach( get_project_list() as $item ) {
echo '<option value="project:' . $item['project_id'] . '">';
echo $item['title'] . "</option>\n";
}
?>
</optgroup>
<optgroup label="Category">
<option value="category:Billable">Billable</option>
<option value="category:Charity">Charity</option>
<option value="category:Personal">Personal</option>
</optgroup>
<optgroup label="Date">
<option value="date:<?php
echo date('m/d/Y', strtotime('-2 Sunday'));
echo ":";
echo date('m/d/Y', strtotime('-1 Saturday'));
?>">Last Week</option>
<option value="date:<?php
echo date('m/d/Y', strtotime('-1 Sunday'));
echo ":";
echo date('m/d/Y');
?>">This Week</option>
<option value="date:<?php
echo date('m/d/Y', strtotime('first day of last month'));
echo ":";
echo date('m/d/Y', strtotime('last day of last month'));
?>">Last Month</option>
<option value="date:<?php
echo date('m/d/Y', strtotime('first day of this month'));
echo ":";
echo date('m/d/Y');
?>">This Month</option>
</optgroup>
</select>
<input class="button" type="submit" value="Run">
</form>
</div>
<div class="section page">
<div class="wrapper">
<table>
<?php
$total = $project_id = $project_total = 0;
$tasks = get_task_list($filter);
foreach($tasks as $key => $item) {
if ($project_id != $item['project_id']) {
$project_id = $item['project_id'];
echo "<thead>\n";
echo "<tr>\n";
echo "<th>" . $item['project'] . "</th>\n";
echo "<th>Date</th>\n";
echo "<th>Time</th>\n";
echo "</tr>\n";
echo "</thead>\n";
}
$project_total += $item['time'];
$total += $item['time'];
echo "<tr>\n";
echo "<td>" . $item['title'] . "</td>\n";
echo "<td>" . $item['date'] . "</td>\n";
echo "<td>" . $item['time'] . "</td>\n";
echo "</tr>\n";
if ( next($tasks)['project_id'] != $item['project_id'] ) {
echo "<tr>\n";
echo "<th class='project-total-label' colspan='2'>Project Total</th>\n";
echo "<th class='project-total-number'>$project_total</th>\n";
echo "</tr>\n";
$project_total = 0;
}
}
?>
<tr>
<th class='grand-total-label' colspan='2'>Grand Total</th>
<th class='grand-total-number'><?php echo $total; ?></th>
</tr>
</table>
</div>
</div>
</div>
</div>
<?php include "inc/footer.php"; ?>
3 Answers
Jennifer Nordell
Treehouse TeacherHi there, Zane DeVault! The next()
function points to the next value in an array. The Notice that you are getting is trying to tell you that when you get to the end of the array, there won't be a next. It will be essentially false
. So at that point, you would be trying to access the key of a boolean. Imagine trying to do false['id']
. It's not going to work, because false
is a boolean.
A notice is not necessarily an error. It's trying to tell you that something could go wrong, but that doesn't mean it will. There are three "levels" in of potential errors. There are errors. These are the most severe and must be corrected. There are warnings which is the mid-range. And there are notices, which is the lowest severity.
Typically, you can disable notices on the server for just this reason. A notice is only telling you that something could be wrong... not necessarily that something is wrong
Hope this helps!
Abdulrahman Al Ani
PHP Development Techdegree Graduate 17,607 Pointsif you want to get rid of this error just to keep the interface clean, you can add this code to the top of your reports.php page right under the opening PHP tags
error_reporting(E_ALL & ~E_NOTICE);
Zane DeVault
42,331 PointsThanks for the tip Abdulrahman Al Ani!
Antony Wright
4,566 PointsMine is coming up as a Warning so added below to stop it showing. is it ok to stop the warning? php7.
error_reporting(E_ALL & ~E_WARNING);
Zane DeVault
42,331 PointsZane DeVault
42,331 PointsThanks Jennifer. So it is totally safe and would be fine to just ignore this Notice, since it's a notice for something that we are expecting to happen?
Jennifer Nordell
Treehouse TeacherJennifer Nordell
Treehouse TeacherZane DeVault that's exactly right. We're expecting to get to the end of the array at some point and for the next element to not exist