Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Java Java Objects Delivering the MVP Applying a Discount Code

Throwing an Illegal Argument Exception error

Why would this code be throwing an Illegal Argument Exception error?

Order.java
public class Order {
  private String itemName;
  private int priceInCents;
  private String discountCode;

  public Order(String itemName, int priceInCents) {
    this.itemName = itemName;
    this.priceInCents = priceInCents;
  }

  public String getItemName() {
    return itemName;
  }

  public int getPriceInCents() {
    return priceInCents;
  }

  public String getDiscountCode() {
    return discountCode;
  }

  public void applyDiscountCode(String discountCode) {
    discountCode = normalizeDiscountCode(discountCode);
    this.discountCode = discountCode;
  }

  private String normalizeDiscountCode(String discountCode){
    for(int i = 0; i < discountCode.length(); i++){
      if(! Character.isLetter(discountCode.charAt(i)) || discountCode.charAt(i) != '$'){
        throw new IllegalArgumentException("Invalid discount code");
      }
    }
    discountCode = discountCode.toUpperCase();
    return discountCode;
  }
}
Example.java
public class Example {

  public static void main(String[] args) {
    // This is here just for example use cases.

    Order order = new Order(
            "Yoda PEZ Dispenser",
            600);

    // These are valid.  They are letters and the $ character only
    order.applyDiscountCode("abc");
    order.getDiscountCode(); // ABC

    order.applyDiscountCode("$ale");
    order.getDiscountCode(); // $ALE


    try {
      // This will throw an exception because it contains numbers
      order.applyDiscountCode("ABC123");
    } catch (IllegalArgumentException iae) {
      System.out.println(iae.getMessage());  // Prints "Invalid discount code"
    }
    try {
      // This will throw as well, because it contains a symbol.
      order.applyDiscountCode("w@w");
    }catch (IllegalArgumentException iae) {
      System.out.println(iae.getMessage());  // Prints "Invalid discount code"
    }

  }
}

1 Answer

Simon Coates
Simon Coates
8,481 Points

This one trips up people. If it's valid if it's a letter OR a $, then it's invalid if it's not a letter AND not a $. You can think this through, but I think it's an application of de morgans law. It seems to accept either of the following.

  private String normalizeDiscountCode(String discountCode){
    for(int i = 0; i < discountCode.length(); i++){
      if(! Character.isLetter(discountCode.charAt(i)) && discountCode.charAt(i) != '$'){
        throw new IllegalArgumentException("Invalid discount code");
      }
    }
    return discountCode.toUpperCase();    
  }

or just inverting the success condition:

    private String normalizeDiscountCode(String discountCode){
    for(int i = 0; i < discountCode.length(); i++){
      if(!
         (Character.isLetter(discountCode.charAt(i)) || discountCode.charAt(i) == '$')
      ){
        throw new IllegalArgumentException("Invalid discount code");
      }
    }
    return discountCode.toUpperCase();    
  }