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Start your free trialMarek Ostrowski
16,268 PointsThere is better way I think: data["Type"] = data["Type"].apply(lambda x: x.replace("Posion", "Poison"))
There is better way I think:
# Posion = Poison
# Fie = Fire
data["Type"] = data["Type"].apply(lambda x: x.replace("Posion", "Poison"))
# with this we have to repeat every row with misspelling. For example:
data.loc[78]["Type"] = "Fire"