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Data Analysis

Marek Ostrowski
Marek Ostrowski
16,543 Points

There is better way I think: data["Type"] = data["Type"].apply(lambda x: x.replace("Posion", "Poison"))

There is better way I think:

# Posion = Poison
# Fie = Fire
data["Type"] = data["Type"].apply(lambda x: x.replace("Posion", "Poison"))

# with this we have to repeat every row with misspelling. For example:
data.loc[78]["Type"] = "Fire"