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Kat Stacy
41,658 PointsThe answer to this question is confusing.
What would be displayed when the following code is executed?
$i = 0; do { echo "$i is greater than 2\n"; $i++; } while ($i > 2);
The correct answer was 0 is greater than 2 Why does this not keep looping until $i becomes 2?
1 Answer
Jason Anders
Treehouse Moderator 145,860 PointsHI Kathryn,
Yep. You're right on! 
do/while loop will always execute once before the condition is even checked.
Keep Coding! :)
Kat Stacy
41,658 PointsThank you, Jason!
Kat Stacy
41,658 PointsMaybe you can help me to solve this complicated logical operator dilemma. https://teamtreehouse.com/community/ping-pong-logical-operators
Kat Stacy
41,658 PointsKat Stacy
41,658 PointsI think I figured it out. It is this way because the condition is not met it will not run. 1 is not greater than 2. For the loop to run the condition $i is greater than 2 must be true. The only reason it runs is that there is a "do" loop/condition before the "while" loop/condition. The "do" condition will make something happen at least once before checking to see if the "while" condition is true. Is that correct?