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Start your free trialIngrid Pettersson
9,916 PointsThe alert doesn't work.
The alert in my code doesn't work. Everything works fine until I add the alert - then nothing works and the console says that it's a SyntaxError with missing ) on that line. It was first identical with Dave's solution in the video and didn't work. After reading the other questions and answers here I added a " after "is" but it still doesn't work. Would be glad for some help!
let firstName = prompt("What is your first name?", "Write your first name here");
let familyName = prompt("What is your family name?", "Write your family name here");
let completeName = firstName.toUpperCase() + ' ' + familyName.toUpperCase();
let characterCount = completeName.length;
alert("The String \"" + completeName + "\" is " + " characterCount + " characters long.");
1 Answer
Brandon White
Full Stack JavaScript Techdegree Graduate 35,771 PointsHey Ingrid Pettersson,
The reason for that syntax error is because your last ) is being treated as if it were part of a string (and not the closing parenthesis for the alert function). I think you may have gotten a bit confused with all of the double quotes and concatenating in that alert function.
My advice would be to re-start the entire string with single quotes, that way you wonโt have to escape your double quotes. If you do this, I think youโll see where youโve opened a string without ending it.
Ingrid Pettersson
9,916 PointsI tried that but still couldn't find the error. Now I learned that the new JavaScript syntax for this alert would be as follows:
alert(The String ${completeName} is ${characterCount} characters long.
);
When I do this it works! Would you say that this is the same function but with newer JS syntax, or is there a difference between the functions?
Brandon White
Full Stack JavaScript Techdegree Graduate 35,771 PointsItโs a newer JS syntax. Itโs called a template string.
Ingrid Pettersson
9,916 PointsThank you Brandon!
Rebecca Meyer
7,962 PointsRebecca Meyer
7,962 Pointsalert(The String ${completeName} is ${characterCount} characters long.);
Hi Ingrid. You forgot to add the backticks here ``