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Start your free trialArtan Muzhaqi
7,983 Pointstask 1 is not working when i go to task 2
my code is not working
<?php
include "pagination.php";
/* add function here */
function pagination($total_pages,$current_page,$section,$search){
/* setting pagination variable */
$pagination = "<div class=\"pagination\">";
$pagination .= "Pages: ";
for ($i = 1;$i <= $total_pages;$i++) {
if ($i == $current_page) {
$pagination .= " <span>$i</span>";
} else {
$pagination .= " <a href='catalog.php?";
if (!empty($search)) {
$pagination .= "s=".urlencode(htmlspecialchars($search)) . '&' ;
} else if (!empty($section)) {
$pagination .= "cat=".$section . '&';
}
$pagination .= "pg=$i'>$i</a>";
}
}
$pagination .= "</div>";
/* displaying the pagination */
return $pagination;
}
echo pagination(10,4,"artan","test");
2 Answers
Ezra Siton
12,644 PointsIn the 1/2 you create the function. Look at the mission:
To use a function for displaying the pagination, we need to pass our function the required variables."
10....4....artan and test are not $vars Change this:
/* displaying the pagination */
echo pagination(10,4,"artan","test");
To this (this is scope trick . Now you pass to the function req vars):
/* displaying the pagination */
echo pagination($total_pages, $current_page, $section, $search);
Ezra Siton
12,644 PointsOne more useful example:
<?php
function foo($var)
{
$var++;
echo $var;
// local scope - result "6";
}
$var=5;
foo($var);
// $var still 5 !!!
echo $var;
// result: 5
?>
Test this idea her: http://www.writephponline.com/
If you want to change the global $var use this: http://php.net/manual/en/language.references.pass.php
Artan Muzhaqi
7,983 PointsArtan Muzhaqi
7,983 Pointsthank you so much. i didn't get that part i just thought that i could pass any variables just to test it.