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Stuart McIntosh
Python Web Development Techdegree Graduate 22,874 PointsSupport with Time_Machine quiz
I am not sure how to pass the string as an argument into the timedelta function. I have attached my code which looks overly complicated and wrong!
import datetime
starter = datetime.datetime(2015, 10, 21, 16, 29)
# Remember, you can't set "years" on a timedelta!
# Consider a year to be 365 days.
## Example
# time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34)
def time_machine(my_int, my_str):
if my_str.upper() == "YEARS":
my_str = "days"
my_int += 365
dt = datetime.timedelta(**{my_str:my_int})
return starter - dt
1 Answer
Ryan S
27,276 PointsHi Stuart,
Actually your code looks pretty good. There are just 2 minor things that are holding it back from passing, but your logic is solid. Your dictionary unpacking in the timedelta is perfectly valid.
First, when you are converting years to days, my_int will need to be multiplied by 365 using the multiplication assignment operator (*=), not addition assignment.
And second, the challenge is looking for a date sometime in the future from "starter", so you will need to use addition in your return statement instead of subtraction.
Good luck.
Stuart McIntosh
Python Web Development Techdegree Graduate 22,874 PointsStuart McIntosh
Python Web Development Techdegree Graduate 22,874 PointsThanks so much for your help.
Happy New Year