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Start your free trialAlbert Egberg
7,786 Points[SOLVED] Change color to blue for each paragraph.
I don't understand why it won't work?
var section = document.querySelectorAll('section');
var paragraphs = section.children;
for (let i = 0; i < paragraphs.length; i += 1) {
paragraphs[i].style.color = 'blue';
}
<!DOCTYPE html>
<html>
<head>
<title>Child Traversal</title>
</head>
<body>
<section>
<p>This is the first paragraph</p>
<p>This is a slightly longer, second paragraph</p>
<p>Shorter, last paragraph</p>
</section>
<footer>
<p>© 2019</p>
</footer>
<script src="app.js"></script>
</body>
</html>
3 Answers
KRIS NIKOLAISEN
54,971 PointsI tried this in a workspace and found in using querySelectorAll
that an index had to be used to access the children even though there was only one section. The following will change the paragraph colors:
var section = document.querySelectorAll("section")[0];
var paragraphs = section.children;
for (let i = 0; i < paragraphs.length; i += 1) {
paragraphs[i].style.color = 'blue';
}
and was accepted by the challenge.
Albert Egberg
7,786 PointsI eventually solved it, but this works aswell! Thanks for the help :)
<noob />
17,062 Pointsvar section = document.querySelector('section');
var paragraphs = section.children;
for(var i = 0; i < paragraphs.length; i++) {
paragraphs[i].style.color = "blue";
}
try to use var instead of let in the loop
<noob />
17,062 Pointstake a look, i will be happy if u can help there :] https://teamtreehouse.com/community/trying-to-filter-options-with-pure-js
Albert Egberg
7,786 PointsYou are too smart for me, I don't understand PHP ;)
Albert Egberg
7,786 PointsAlbert Egberg
7,786 PointsIf I'd change the fitst line of code to:
const section = document.querySelectorAll('section');
it'd work.