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Aboudi ABU SAMRA
1,000 PointsSo confused
I start the script and when I press any letter it prints forever
import random
# make a list of words
words = [
'apple'
'banana',
'orange',
'coconut',
'strawberry',
'lime',
'grapefruit',
'lemon',
'kumquat',
'blueberry',
'melon'
]
while True:
start = input("""Press enter/return to start, or Q to quit:
>> """)
if start.lower == 'q':
break
# pick a random word
secret_word = random.choice(words)
bad_guesses = []
good_guesses = []
while len(bad_guesses) < 7 and len(good_guesses) != len(list(secret_word)):
# draw spaces
# draw guessed letters and stricks
for letter in secret_word:
if letter in good_guesses:
print(letter, end='')
else:
print('_', end='')
print('')
print('Strikes: {}/7'.format(len(bad_guesses)))
print('')
# take guess
#print out win/lose
[MOD: added ```python formatting -cf]
1 Answer
Chris Freeman
Treehouse Moderator 68,457 PointsCurrently, the second while statement has no exit. Add more code to ask for guesses thus the bad_guesses will break out of the loop eventually.
This is the danger of coding while loops: make sure the the loop exit code is understood or programmed first.
Post back if you have more questions. Good Luck!!!
Aboudi ABU SAMRA
1,000 PointsAboudi ABU SAMRA
1,000 Pointswhere do I place the exit?
Chris Freeman
Treehouse Moderator 68,457 PointsChris Freeman
Treehouse Moderator 68,457 PointsIt's not necessarily a literal "exit". Rather, it is either a
breakstatement or something that will eventually cause thewhileconditions to fail.In extreme debug situations, due to code that has a lot of code yet to be implemented, I'll add counter to limit the
whileloops. A sort of "override". Once the code is working the override safety breakout can be removed.A simple way to add this: