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Start your free trialAakash Srivastav
Full Stack JavaScript Techdegree Student 11,638 Pointsreversing array with for loop
Why doesn't initializing n
within the for
loop reverse the order of array elements.
My code is-
var lotOfNames = ["Aakash" , "Shubham" , "Ankit" , "Shanu"];
function reverseArray( newArray ){
for( let i = 0 ; i < Math.floor(n/2) ; i++){
var n = newArray.length;
let temp = newArray[i];
newArray[i] = newArray[n-i-1];
newArray[n-i-1] = temp;
}
return newArray;
}
console.log(reverseArray(lotOfNames));
When I run this code . It prints the same array.
But when I initialised n
outside for
loop , function works and it print the reverse order of elements as expected.
I know its silly to do such thing. But i was just experimenting with the code.
1 Answer
Steven Parker
231,275 PointsThe loop depends on the value of "n" in the condition clause ("i < Math.floor(n / 2)
"). So if "n" is not established before the loop starts, then the condition is false
to start with and the loop does not run.