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Java Java Objects Creating the MVP Scrabble Tiles

Posted by Nkosinolwazi Moyo
Nkosinolwazi Moyo
9,588 Points

Return true

Help, I'm failing to give an expression that uses the index of a char in a String.

ScrabblePlayer.java 
public class ScrabblePlayer {
  // A String representing all of the tiles that this player has
  private String tiles;

  public ScrabblePlayer() {
    tiles = "t";
  }

  public String getTiles() {
    return tiles;
  }

  public void addTile(char tile) {
    // TODO: Add the tile to tiles
  tiles += "t" ; 
  }

  public boolean hasTile(char tile) {
    // TODO: Determine if user has the tile passed in
    return false;

  }

}

1 Answer

Tonnie Fanadez
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.a{fill-rule:evenodd;}techdegree seal-36
Tonnie Fanadez
UX Design Techdegree Graduate 22,796 Points
Tonnie Fanadez
.a{fill-rule:evenodd;}techdegree seal-36
Tonnie Fanadez
UX Design Techdegree Graduate 22,796 Points

Hi, great to see you around.

This is how I approached the first problem. I took the field tiles declared and the top of class and added char tile to it using += operator. 

public void addTile(char tile) {
    // TODO: Add the tile to tiles
    tiles+= tile;
  }

For the second task I created a boolean hasLetter and I set it to false. I then went for the for-loop to iterate through the characters contained inside tiles. I used *String.toCharArray().length * method to convert the tiles to an array of characters and get the number of letters.

Lastly, I used *String.indexOf( char) * which returns ** -1 ** if the character is not found, if the character is found, it returns a number that is greater or equal to zero.

public boolean hasTile(char tile) {
    // TODO: Determine if user has the tile passed in

    boolean hasLetter = false;
    for(int i =0; i<tiles.toCharArray().length; i++){

   hasLetter = ( tiles.indexOf(tile) >=0);

    }
    return hasLetter;
}

The for-each also works fine as demonstrated below

public boolean hasTile(char tile) {
    // TODO: Determine if user has the tile passed in
    boolean hasLetter = false;
    for(Character letter: tiles.toCharArray()){

      hasLetter =tiles.indexOf(tile)>=0;
    }
    return hasLetter;
  }

Happy coding Nkosinolwazi Moyo