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![Andy McDonald](https://secure.gravatar.com/avatar/2c7a70bb997cb62e77a9341481bf2b27?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Andy McDonald
Python Development Techdegree Graduate 13,801 Pointsre not defined???
I dont understand why this isnt working. When I run the script in another program it seems to work fine.
import re
def splitsville(address):
answer = re.search(r"(?P<street>[\w]+\s[\w\d]+\s[\w\d]+\s[\w]+),\s(?P<city>[\w]+),\s(?P<state>[\w]+),\s(?P<zipcode>[\d]+)", address)
return answer.groupdict()
1 Answer
![Jeff Muday](https://uploads.teamtreehouse.com/production/profile-photos/5900142/micro_jeff_face.jpg)
Jeff Muday
Treehouse Moderator 28,718 PointsI like how you think-- the regular expression would have been a nice way to solve this! However, this Challenge doesn't have re
(regular expressions) in its namespace, go figure! You can try using split
and strip
. That will work.
My regular expression solution would have been this. I am using the |
pipe character and square brackets to define the expression. For example, I write for the street (?P<street>[\d+|\w+|\s]+), which means I can have one or more digits \d+
or letters \w+
or whitespace \s
separating the street.
With regular expressions, there are SO MANY ways to do this, many correct answers!
import re
def splitsville(address):
answer = re.search(r"(?P<street>[\d+|\w+|\s]+),\s(?P<city>[\w+|\s]+),\s(?P<state>[\w+|\s]+),\s(?P<zip_code>[\d]+)", address)
return answer.groupdict()