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![Greg Taylor](https://secure.gravatar.com/avatar/ca3ea3c1166f1a9728e6c24cfae8c674?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Greg Taylor
798 PointsRandom Number Challenge - two numbers solutions
I tried it this way and it also worked, what do you think? Won't it cause some errors based on different user inputs.
1 Answer
![Steven Parker](https://uploads.teamtreehouse.com/production/profile-photos/969492/micro_tool_chess_set_2.jpg)
Steven Parker
230,688 PointsOne issue is with the testing of the numbers as if they were Boolean (if (wholeNumber && wholeNumber2)
). If either number input is 0, this will be interpreted as false just as a NaN would be. To avoid this, you can check the numbers using isNaN: if (!isNaN(wholeNumber) && !isNaN(wholeNumber2))
.
Also Math.random does not take an argument, and the formula used is not correct for selecting a number inclusively between two limits. The correct formula would be: Math.floor(Math.random() * (wholeNumber - wholeNumber2 + 1) + wholeNumber2)
.