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Erik Embervine
Python Development Techdegree Student 2,442 PointsQuiz question 1 solution seems redundant?
it looks like 2 copies of the restaurants list was made before looping through them to eliminate the non-taco restaurants...is this necessary? i cut down the code to be this:
all_restaurants = [
"Taco City",
"Burgertown",
"Tacovilla",
"Hotdog station",
"House of tacos",
]
def tacos_only(restaurants):
for restaurant in restaurants.copy():
if "taco" not in restaurant.lower():
restaurants.remove(restaurant)
return restaurants
dinner_options = tacos_only(all_restaurants)
print(dinner_options)
...and it seems to do the same thing. is the taco_joints reassignment and taco_joints.copy necessary?
1 Answer
![Steven Parker](https://uploads.teamtreehouse.com/production/profile-photos/969492/micro_tool_chess_set_2.jpg)
Steven Parker
230,688 PointsThe creation of taco_joints allows the function to return a modified list without changing the original list.
With the modifications shown above, the function will alter the original list of all_restaurants.
Erik Embervine
Python Development Techdegree Student 2,442 PointsErik Embervine
Python Development Techdegree Student 2,442 Pointsok I see. thanks!