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Java Java Data Structures - Retired Organizing Data Splitting Strings

Posted by kristoffer tølbøll
kristoffer tølbøll
1,337 Points

question regarding ! and integers

Can someone explain this

public static void main(String[] args){ int i = 7; int j = 12; if(!(i == 7 || j == 7)){ System.out.println("Fire"); } else { System.out.println("Water"); } } }

why is the outcome Water and not fire?

1 Answer

Damien Watson
Damien Watson
27,419 Points
Damien Watson
Damien Watson
27,419 Points

Hey, the ! symbol means 'not', so if it is !(int i == 7) then it means if 'i' is not equal to 7, which it is, so it fails and shows water.

public static void main(String[] args){
  int i = 7;
  int j = 12;
  // if not (i==7 OR j==7) but i does == 7, so show Water
  if(!(i == 7 || j == 7)){
    System.out.println("Fire");
  } else {
    System.out.println("Water");
  }
}