Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialErik Pelletier
14,673 PointsProper syntax being rejected for $.getJSON() function - var jqxhr = $.getJSON(weatherAPI,objData,showWeather(data));
I've tried every incarnation of this function call, including reference from jQuery docs. Nothing works.
$(document).ready(function() {
var weatherAPI = 'http://api.openweathermap.org/data/2.5/weather';
var objData = {
q : "Portland,OR",
units : "metric"
};
function showWeather(weatherReport) {
$('#temperature').text(weatherReport.main.temp);
}
var jqxhr = $.getJSON(weatherAPI,objData,showWeather(data));
});
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>What's the Weather Like?</title>
<script src="jquery.js"></script>
<script src="weather.js"></script>
</head>
<body>
<div id="main">
<h1>Current temperature: <span id="temperature"></span>°</h1>
</div>
</body>
</html>
1 Answer
Seth Kroger
56,414 PointsYou need to pass the function without calling it. Calling the function executes it immediately and passes what the function returns, which is nothing in this case. You need to refer to the function so it can be called later.
$.getJSON(weatherAPI, objData, showWeather);