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JavaScript JavaScript and the DOM (Retiring) Traversing the DOM Child Traversal

James Falconi
James Falconi
5,375 Points

"Programatically" selecting all child nodes to change color with for loop.

I have the following to iterate through the children of a section. It's not getting all the children though. What am I missing?

const section = document.querySelector('section'); let paragraphs = section.children;

for (let i = 0; i < paragraphs; i++) { paragraphs[i].style.color = 'blue'; }

app.js
const section = document.querySelector('section');
let paragraphs = section.children;

for (let i = 0; i < paragraphs; i++) {
  paragraphs[i].style.color = 'blue';
}
index.html
<!DOCTYPE html>
<html>
    <head>
        <title>Child Traversal</title>
    </head>
    <body>
        <section>
            <p>This is the first paragraph</p>
            <p>This is a slightly longer, second paragraph</p>
            <p>Shorter, last paragraph</p>
        </section>
        <footer>
            <p>&copy; 2016</p> 
        </footer>
        <script src="app.js"></script>
    </body>
</html>

2 Answers

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there! It seems like you're not new to arrays. So would it be helpful if you had this hint? The section.children returns an array of elements. And you're looping through the array until the last element. You can find out where the last index is by getting the length of the array (which is paragraphs).

I think you can get it with these hints, but let me know if you're still stuck! :sparkles:

James Falconi
James Falconi
5,375 Points

AH. I had forgotten ".length" on the for loop.