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Treehouse Project Reviewerplease can somebody excplain what i do wrong
It has to be checked if the argument is integer or not
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(num=''):
try:
if int(num) == num:
return int(num)**2
if int(num) != num:
return num*len(num)
except Exception:
pass
1 Answer
Steven Parker
231,275 PointsYou're trying too hard.
This function won't take so many lines of code. Here's some hints:
- you should only need to do an int() conversion one time
- if no exception occurs, you can immediately return the square of the converted number
- you won't need to compare the number with anything
- if an exception does occur, return the string expanded by its length (don't "pass")
Oszkár Fehér
Treehouse Project ReviewerOszkár Fehér
Treehouse Project ReviewerThis was the first thing what i was thinking but because it written "If the nr can be converted...or If can't..." i thought for the quiz i have to make it whit "if" statement. thank you