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Start your free trialLinda Gomes
3,584 PointsOn line 2 of app.js, select all links in the unordered list with the id of "gallery" and assign them to galleryLinks.
I don't understand why it doesn't work. It says "Was expecting 2 links not 3"
let navigationLinks = document.querySelectorAll('nav a'); let galleryLinks = document.querySelectorAll('#gallery'); let footerImages;
let navigationLinks = document.querySelectorAll('nav a');
let galleryLinks = document.querySelectorAll('#gallery');
let footerImages;
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Nick Pettit | Designer</title>
<link rel="stylesheet" href="css/normalize.css">
<link href='http://fonts.googleapis.com/css?family=Changa+One|Open+Sans:400italic,700italic,400,700,800' rel='stylesheet' type='text/css'>
<link rel="stylesheet" href="css/main.css">
<link rel="stylesheet" href="css/responsive.css">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
</head>
<body>
<header>
<a href="index.html" id="logo">
<h1>Nick Pettit</h1>
<h2>Designer</h2>
</a>
<nav>
<ul>
<li><a href="index.html" class="selected">Portfolio</a></li>
<li><a href="about.html">About</a></li>
<li><a href="contact.html">Contact</a></li>
</ul>
</nav>
</header>
<div id="wrapper">
<section>
<ul id="gallery">
<li>
<a href="img/numbers-01.jpg">
<img src="img/numbers-01.jpg" alt="">
<p>Experimentation with color and texture.</p>
</a>
</li>
<li>
<a href="img/numbers-02.jpg">
<img src="img/numbers-02.jpg" alt="">
<p>Playing with blending modes in Photoshop.</p>
</a>
</li>
</ul>
</section>
<footer>
<a href="http://twitter.com/nickrp"><img src="img/twitter-wrap.png" alt="Twitter Logo" class="social-icon"></a>
<a href="http://facebook.com/nickpettit"><img src="img/facebook-wrap.png" alt="Facebook Logo" class="social-icon"></a>
<p>© 2016 Nick Pettit.</p>
</footer>
</div>
<script src="js/app.js"></script>
</body>
</html>
1 Answer
Jason Anders
Treehouse Moderator 145,860 PointsHey Linda,
For Task 2, you are going to have to string together a couple of selectors. First you need to access the ID of gallery
using getElementById()
, and then string on the second one to select the links inside with getElementsByTagName()
. So, one selects the ID and then because of chaining, the second one will select only the tags inside of the ID.
let galleryLinks = document.getElementById('gallery').getElementsByTagName('a');
Hope the helps. :)
Linda Gomes
3,584 PointsLinda Gomes
3,584 PointsThank you so much! This DOM thing is very tricky... I'm finding it very hard to understand. But (very) slowly I think I'll get there.