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Start your free trialMichal Dobrzynski
3,490 PointsNot sure if using the right query in this one, or selecting the wrong object, i.e. the list elements instead of parent
Not sure if using the right query in this one, or selecting the wrong object, i.e. the list elements instead of parent
<!DOCTYPE html>
<html>
<head>
<title>Rainbow!</title>
</head>
<body>
<ul id="rainbow">
<li>This should be red</li>
<li>This should be orange</li>
<li>This should be yellow</li>
<li>This should be green</li>
<li>This should be blue</li>
<li>This should be indigo</li>
<li>This should be violet</li>
</ul>
<script src="js/app.js"></script>
</body>
</html>
let listItems = document.querySelectorAll("li");
console.log(listItems);
const colors = ["#C2272D", "#F8931F", "#FFFF01", "#009245", "#0193D9", "#0C04ED", "#612F90"];
for(var i = 0; i < colors.length; i ++) {
listItems[1].style.color = colors[i];
}
1 Answer
Leandro Botella Penalva
17,618 PointsHi Michal,
Inside the for loop you are picking always the second element of the listItems array "listItems[1]". Instead you should use the "i" counter of the loop like this: listItems[i]
Michal Dobrzynski
3,490 PointsMichal Dobrzynski
3,490 PointsMany thanks Leandro, it seems that I need glasses after all :D
Managed to get it to work in the meantime by resetting the code and thus correcting the typo.