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Python Python Basics (2015) Logic in Python Conditional Value

Posted by Peckeday Slossar
Peckeday Slossar
1,069 Points

Not sure how to go about this challenge.... Every time I add a line of code for if statement get syntax error on line 1

Please help

conditions.py 
admitted = None
if admitted <= 13

2 Answers

Steven Parker
Steven Parker
231,275 Points
Steven Parker
Steven Parker
231,275 Points

Here's a few hints:

  • the challenge said, "I need you to make an if condition that sets admitted to True if age is 13 or more."
  • so you don't want to test admitted, you want to test age
  • you want to test for 13 or more, but "<= 13" tests for 13 or less
  • the "if" statement should end with a colon (":")
  • after the "if" line you'll need an assignment statement (this time, for admitted)
Peckeday Slossar
Peckeday Slossar
1,069 Points

Ok got it. Ok so I tried this and now it says "age isnt = True"

admitted = None if age <= 13: age = True also tried

admitted = None if age <= 13: if not age > 13: admitted = True

and get the same result

Steven Parker
Steven Parker
231,275 Points
Steven Parker
Steven Parker
231,275 Points

That first one is close but it still uses "<= 13" which tests for 13 or less. But the instructions say to test for "13 or more". There's another operator (also a pair of symbols) which has that meaning.

Also, when posting code, always use the instructions for code formatting in the Markdown Cheatsheet pop-up below the "Add an Answer" area. :arrow_heading_down: Or watch this video on code formatting.

Peckeday Slossar
Peckeday Slossar
1,069 Points
Peckeday Slossar
Peckeday Slossar
1,069 Points

Ok I got it now. It was a simple syntax error stopping me on the 2nd step. It said Task 1 is no longer passing which confused me. I structured it like this

admitted = None
   if >= 13:
      admitted = True
      else:
         admitted = False

when I should have structured it like this

admitted = None
if age >= 13:
   admitted = True
else:
   admitted = False

Appreciate the help Steven