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Python Regular Expressions in Python Introduction to Regular Expressions Email Groups

need, help, what am i doing wrong

Help needed

emails.py
import re

string = '''Love, Kenneth, kenneth+challenge@teamtreehouse.com, 555-555-5555, @kennethlove
Chalkley, Andrew, andrew@teamtreehouse.co.uk, 555-555-5556, @chalkers
McFarland, Dave, dave.mcfarland@teamtreehouse.com, 555-555-5557, @davemcfarland
Kesten, Joy, joy@teamtreehouse.com, 555-555-5558, @joykesten'''
contacts = re.search(r''' #<-- Wrap in multiline quote. Remove leading caret (^)
    (?P<email>[-\w\d.+]+@[-\w\d.]+) 
     ,\s
     (?P<phone>\d{3}-\d{3}-\d{4})''' #<-- Add closing paren. Remove extra backslashes. Remove trailing $
     , string, re.X | re.M)

twitters = re.search(r'''
    (?P<twitter>@[\w\d]+)?$
''', string, re.X | re.M)

2 Answers

Dan Johnson
Dan Johnson
40,533 Points

The ? means optional, as in zero or one of something. Since you have that outside the twitter group it makes that entire group optional. Get rid of it and you should get rid of the extra capture.

just by taking that out it passed, after 3 hours of trying you helped, thank you

TASk 1 & 2 with the help from Dan johson

contacts = re.search(r''' #<-- Wrap in multiline quote. Remove leading caret (^) (?P<email>[-\w\d.+]+@[-\w\d.]+) ,\s (?P<phone>\d{3}-\d{3}-\d{4})''' #<-- Add closing paren. Remove extra backslashes. Remove trailing $ , string, re.X | re.M)

twitters = re.search(r''' (?P<twitter>@[\w\d]+)$ ''', string, re.X | re.M)