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Start your free trialLewis Marshall
22,673 PointsMy solution to handle invalid query string key 'side' value
router.get('/:id', (req, res) => {
const { id } = req.params;
const { side } = req.query;
// checks the side value is included in the array
const invalidQueryString = !["question", "answer"].includes(side);
if (!side || invalidQueryString) {
res.redirect(`/cards/${id}?side=question`);
} else {
const name = req.cookies.username;
const text = cards[id][side];
const { hint } = cards[id];
const templateData = { text, id, side, name };
if (side === "question") {
templateData.hint = hint;
}
res.render('card', templateData);
}
});
1 Answer
Trevor Maltbie
Full Stack JavaScript Techdegree Graduate 17,021 PointsGood thinking, Lewis. Using the includes method is a good approach.
I had thought of something similar:
if ( side !== 'answer' || side !== 'question' ) {
res.redirect(`/cards/${id}?side=question`)
}
However, this leads to an infinite amount of redirects and crashes the site.
EDIT: I just realized that this is failing because if || operator. If it's not answer but it is question it just keeps bouncing back and forth.
The solution is to make use && operator.