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Start your free trialKeenan Smith
Python Development Techdegree Student 5,487 PointsMy search_challenge function doesn't work
I thought I was adding the function correctly, but im getting a syntax error. Am i missing something else?
from models import Challenge
def create_challenge(name, language, steps=1):
Challenge.create(name=name,
language=language,
steps=steps)
def search_challenges():
challenge = challenge.where(Challenge.content.contains(name, language)
1 Answer
Joseph Yhu
PHP Development Techdegree Graduate 48,637 PointsYour code (for reference):
def search_challenges():
challenge = challenge.where(Challenge.content.contains(name, language)
Two basic things first:
- Your function needs to have two parameters: name and language.
- Your function needs to return a value, which is all
Challenge
s that meet the criteria.
Now for the specifics:
- You don't have to create a variable called
challenge
and assign the results of the query to it; you can just return the query results. - The
c
inchallenge.where
should be capitalized. - You should have a
select()
in betweenChallenge
andwhere
. -
Challenge.name
must contain thename
argument, butChallenge.language
must equal thelanguage
argument.
My solution:
def search_challenges(name, language):
return Challenge.select().where(Challenge.name.contains(name), Challenge.language == language)